簡(jiǎn)介:2017年全國(guó)碩士研究生入學(xué)統(tǒng)一考試英語(yǔ)(二)SECTIONIUSEOFENGLISHDIRECTIONSREADTHEFOLLOWINGTEXTCHOOSETHEBESTWORDSFOREACHNUMBEREDBLANKANDMARKA,B,CORDONTHEANSWERSHEET10POINTSPEOPLEHAVESPECULATEDFORCENTURIESABOUTAFUTUREWITHOUTWORKTODAYISNODIFFERENT,WITHACADEMICS,WRITERS,ANDACTIVISTSONCEAGAIN1THATTECHNOLOGYBEREPLACINGHUMANWORKERSSOMEIMAGINETHATTHECOMINGWORKFREEWORLDWILLBEDEFINEDBY2AFEWWEALTHYPEOPLEWILLOWNALLTHECAPITAL,ANDTHEMASSESWILLSTRUGGLEINANIMPOVERISHEDWASTELANDADIFFERENTANDNOTMUTUALLYEXCLUSIVE3HOLDSTHATTHEFUTUREWILLBEAWASTELANDOFADIFFERENTSORT,ONE4BYPURPOSELESSNESSWITHOUTJOBSTOGIVETHEIRLIVES5,PEOPLEWILLSIMPLYBECOMELAZYANDDEPRESSED6,TODAY’SUNEMPLOYEDDON’TSEEMTOBEHAVINGAGREATTIMEONEGALLUPPOLLFOUNDTHAT20PERCENTOFAMERICANSWHOHAVEBEENUNEMPLOYEDFORATLEASTAYEARREPORTHAVINGDEPRESSION,DOUBLETHERATEFOR7AMERICANSALSO,SOMERESEARCHSUGGESTSTHATTHE8FORRISINGRATESOFMORTALITY,MENTALHEALTHPROBLEMS,ANDADDICTING9POORLYEDUCATEDMIDDLEAGEDPEOPLEISSHORTAGEOFWELLPAIDJOBSPERHAPSTHISISWHYMANY10THEAGONIZINGDULLNESSOFAJOBLESSFUTUREBUTITDOESN’T11FOLLOWFROMFINDINGSLIKETHESETHATAWORLDWITHOUTWORKWOULDBEFILLEDWITHUNEASESUCHVISIONSAREBASEDONTHE12OFBEINGUNEMPLOYEDINASOCIETYBUILTONTHECONCEPTOFEMPLOYMENTINTHE13OFWORK,ASOCIETYDESIGNEDWITHOTHERENDSINMINDCOULD14STRIKINGLYDIFFERENTCIRCUMSTANCEDFORTHEFUTUREOFLABORANDLEISURETODAY,THE15OFWORKMAYBEABITOVERBLOWN“MANYJOBSAREBORING,DEGRADING,UNHEALTHY,ANDAWASTEOFHUMANPOTENTIAL,”SAYSJOHNDANAHER,ALECTURERATTHENATIONALUNIVERSITYOFIRELANDINGALWAYTHESEDAYS,BECAUSELEISURETIMEISRELATIVELY16FORMOSTWORKERS,PEOPLEUSETHEIRFREETIMETOCOUNTERBALANCETHEINTELLECTUALANDEMOTIONAL17OFTHEIRJOBS“WHENICOMEHOMEFROMAHARDDAY’SWORK,IOFTENFEEL18,”DANAHERSAYS,ADDING,“INAWORLDINWHICHIDON’THAVETOWORK,IMIGHTFEELRATHERDIFFERENT”PERHAPSDIFFERENTENOUGHTOTHROWHIMSELF19AHOBBYORAPASSIONPROJECTWITHTHEINTENSITYUSUALLYRESERVEDFOR20MATTERS1.ABOASTINGBDENYINGCWARNINGDENSURING【答案】CWARNING【答案】DAMONG10.ALEAVEBEHINDBMAKEUPCWORRYABOUTDSETASIDE【答案】CWORRYABOUT11.ASTATISTICALLYBOCCASIONALLYCNECESSARILYDECONOMICALLY【答案】CNECESSARILY12.ACHANCESBDOWNSIDESCBENEFITSDPRINCIPLES【答案】BDOWNSIDES13.AABSENCEBHEIGHTCFACEDCOURSE【答案】AABSENCE14.ADISTURBBRESTORECEXCLUDEDYIELD【答案】DYIELD15.AMODELBPRACTICECVIRTUEDHARDSHIP【答案】CVIRTUE16.ATRICKYBLENGTHYCMYSTERIOUSDSCARCE【答案】DSCARCE
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簡(jiǎn)介:普通高等學(xué)校招生全國(guó)統(tǒng)一考試數(shù)學(xué)真題2014年普通高等學(xué)校招生全國(guó)統(tǒng)一考試課標(biāo)全國(guó)Ⅱ數(shù)學(xué)理科第Ⅰ卷一、選擇題本大題共12小題,每小題5分,在每小題給出的四個(gè)選項(xiàng)中,只有一項(xiàng)是符合題目要求的12014課標(biāo)全國(guó)Ⅱ,理1設(shè)集合M{0,1,2},N{X|X23X2≤0},則M∩NA{1}B{2}C{0,1}D{1,2}答案D解析∵M(jìn){0,1,2},N{X|X23X2≤0}{X|1≤X≤2},∴M∩N{0,1,2}∩{X|1≤X≤2}{1,2}故選D22014課標(biāo)全國(guó)Ⅱ,理2設(shè)復(fù)數(shù)Z1,Z2在復(fù)平面內(nèi)的對(duì)應(yīng)點(diǎn)關(guān)于虛軸對(duì)稱,Z12I,則Z1Z2A5B5C4ID4I答案A解析由題意知Z22I又Z12I,所以Z1Z22I2II245故選A32014課標(biāo)全國(guó)Ⅱ,理3設(shè)向量A,B滿足|AB|,|AB|,則AB106A1B2C3D5答案A解析∵|AB|,∴AB210,10即A2B22AB10①∵|AB|,∴AB26,6即A2B22AB6②由①②可得AB1故選A42014課標(biāo)全國(guó)Ⅱ,理4鈍角三角形ABC的面積是,AB1,BC,則AC122A5BC2D15答案B解析由題意知S△ABCABBCSINB,12即1SINB,解得SINB1212222∴B45°或B135°當(dāng)B45°時(shí),AC2AB2BC22ABBCCOSB1222112222此時(shí)AC2AB2BC2,△ABC為直角三角形,不符合題意當(dāng)B135°時(shí),AC2AB2BC22ABBCCOSB122215,解得AC符合題意故選22225B52014課標(biāo)全國(guó)Ⅱ,理5某地區(qū)空氣質(zhì)量監(jiān)測(cè)資料表明,一天的空氣質(zhì)量為優(yōu)良的概率是075,連續(xù)兩天為優(yōu)良的概率是06,已知某天的空氣質(zhì)量為優(yōu)良,則隨后一天的空氣質(zhì)量為優(yōu)良的概率是A08B075C06D045答案A解析設(shè)某天空氣質(zhì)量為優(yōu)良為事件A,隨后一天空氣質(zhì)量為優(yōu)良為事件B,由已知得PA075,PAB06,所求事件的概率為PB|A08,故選APABPA0607562014課標(biāo)全國(guó)Ⅱ,理6如圖,網(wǎng)格紙上正方形小格的邊長(zhǎng)為1表示1CM,圖中粗線畫出的是某零件的三視圖,該零件由一個(gè)底面半徑為3CM,高為6CM的圓柱體毛坯切削得到,則切削掉部分的體積與原來(lái)毛坯體積的比值為普通高等學(xué)校招生全國(guó)統(tǒng)一考試數(shù)學(xué)真題將直線L0Y2X平行移動(dòng),當(dāng)直線L0經(jīng)過(guò)點(diǎn)M5,2時(shí),直線Y2XZ在Y軸上的截距最小,也就是Z取最大值,此時(shí)ZMAX2528102014課標(biāo)全國(guó)Ⅱ,理10設(shè)F為拋物線CY23X的焦點(diǎn),過(guò)F且傾斜角為30°的直線交C于A,B兩點(diǎn),O為坐標(biāo)原點(diǎn),則△OAB的面積為ABCD334938633294答案D解析由已知得F,故直線AB的方程為YTAN30°,即YX34,0X343334設(shè)AX1,Y1,BX2,Y2,聯(lián)立{Y33X34,Y23X,??①②?將①代入②并整理得X2X0,1372316∴X1X2,212∴線段|AB|X1X2P1221232又原點(diǎn)0,0到直線AB的距離為D3413138∴S△OAB|AB|D1212123894112014課標(biāo)全國(guó)Ⅱ,理11直三棱柱ABCA1B1C1中,∠BCA90°,M,N分別是A1B1,A1C1的中點(diǎn),BCCACC1,則BM與AN所成角的余弦值為ABCD11025301022答案C解析如圖,以點(diǎn)C1為坐標(biāo)原點(diǎn),C1B1,C1A1,C1C所在的直線分別為X軸,Y軸,Z軸,建立空間直角坐標(biāo)系,不妨設(shè)BCCACC11,可知點(diǎn)A0,1,1,N,B1,0,1,M0,12,012,12,0∴AN0,12,1,BM12,12,1∴COSAN,BMANBM|AN||BM|3010根據(jù)的夾角及AN與BM所成角的關(guān)系可知,BM與AN所成角的余弦值為AN與BM3010122014課標(biāo)全國(guó)Ⅱ,理12設(shè)函數(shù)FXSIN若存在FX的極值點(diǎn)X0滿足FX02M2,則M的取值范圍是3XM20
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